4m^2-m-39=0

Solution for 4m^2-m-39=0 equation:

4m^2-m-39=0

We add all the numbers together, and all the variables

4m^2-1m-39=0

a = 4; b = -1; c = -39;
Δ = b2-4ac
Δ = -12-4·4·(-39)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-25}{2*4}=\frac{-24}{8}
=-3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+25}{2*4}=\frac{26}{8}
=3+1/4
$